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JEE Mains · Physics · STD 11 - 13. oscillations

An oscillator of mass \(M\)  is at rest in its equilibrium position in a potential \(V\, = \,\frac{1}{2}\,k{(x - X)^2}.\) A particle of mass \(m\)  comes from right with speed \(u\)  and collides completely inelastically with \(M\) and sticks to it . This process repeats every time the oscillator crosses its equilibrium position .The amplitude of oscillations after \(13\)  collisions is: \((M = 10,\, m = 5,\, u = 1,\, k = 1 ).\) 

  1. A \(\frac {1}{2}\)
  2. B \(\frac {1}{\sqrt 3}\)
  3. C \(\frac {2}{3}\)
  4. D \(\sqrt {\frac {3}{5}}\)
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Answer & Solution

Correct Answer

(B) \(\frac {1}{\sqrt 3}\)

Step-by-step Solution

Detailed explanation

In first collision \(mu\) momentum will be imparted to system, in second collision when momentum of \((\mathrm{M}+\mathrm{m})\) is in opposite direction \(mu\) momentum of particle will make its momentum zero. On \(13^{\text {th }}\) collision,…
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