JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2018
- Hard
- MCQ
The energy required to remove the electron from a singly ionized Helium atom is \(2.2\, times\) the energy required to remove an electron from Helium atom . The total energy required to ionize the Helium atom completely is......\(eV\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(79\)
Step-by-step Solution
Detailed explanation
Energy required to remove e - from singly
ionized helium atom \({ = \frac{{(13.6){Z^2}}}{{{1^2}}} = 54.4\,{\text{eV}}}\)
\((\because Z=2)\)
Energy required to remove \(e^-\) from helium atom \(=x\,eV\)
According to question, \(54.4 \mathrm{eV}=2.2 \mathrm{x} \Rightarrow \mathrm{x}\)
\(=24.73 \mathrm{eV}\)
Therefore, energy required to ionize helium atom \(=(54.4+24.73)eV\) \(=79.12 \mathrm{eV}\)
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