ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2018
  • Hard
  • MCQ

The energy required to remove the electron from a singly ionized Helium atom is \(2.2\, times\) the energy required to remove an electron from Helium atom . The total energy required to ionize the Helium atom completely is......\(eV\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(79\)

Step-by-step Solution

Detailed explanation

Energy required to remove e - from singly

ionized helium atom \({ = \frac{{(13.6){Z^2}}}{{{1^2}}} = 54.4\,{\text{eV}}}\)

\((\because Z=2)\)

Energy required to remove \(e^-\) from helium atom \(=x\,eV\)

According to question, \(54.4 \mathrm{eV}=2.2 \mathrm{x} \Rightarrow \mathrm{x}\)

\(=24.73 \mathrm{eV}\)

Therefore, energy required to ionize helium atom \(=(54.4+24.73)eV\) \(=79.12 \mathrm{eV}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app