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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

The matrix \(A^2 + 4A - 5I\), where \(I\) is identity matrix and \(A = \left[ {\begin{array}{*{20}{c}}
1&2\\
4&{ - 3}
\end{array}} \right]\) , equals

  1. A \(4\left[ {\begin{array}{*{20}{c}}
    2&1\\
    2&0
    \end{array}} \right]\)
  2. B \(4\left[ {\begin{array}{*{20}{c}}
    0&{ - 1}\\
    2&2
    \end{array}} \right]\)
  3. C \(32\left[ {\begin{array}{*{20}{c}}
    2&1\\
    2&0
    \end{array}} \right]\)
  4. D \(32\left[ {\begin{array}{*{20}{c}}
    1&1\\
    1&0
    \end{array}} \right]\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4\left[ {\begin{array}{*{20}{c}}
2&1\\
2&0
\end{array}} \right]\)

Step-by-step Solution

Detailed explanation

\({A^2} + 4A - 51 = A \times A + 4A - 5I\)…
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