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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
The matrix \(A^2 + 4A - 5I\), where \(I\) is identity matrix and \(A = \left[ {\begin{array}{*{20}{c}}
1&2\\
4&{ - 3}
\end{array}} \right]\) , equals
- A \(4\left[ {\begin{array}{*{20}{c}}
2&1\\
2&0
\end{array}} \right]\) - B \(4\left[ {\begin{array}{*{20}{c}}
0&{ - 1}\\
2&2
\end{array}} \right]\) - C \(32\left[ {\begin{array}{*{20}{c}}
2&1\\
2&0
\end{array}} \right]\) - D \(32\left[ {\begin{array}{*{20}{c}}
1&1\\
1&0
\end{array}} \right]\)
Answer & Solution
Correct Answer
(A) \(4\left[ {\begin{array}{*{20}{c}}
2&1\\
2&0
\end{array}} \right]\)
Step-by-step Solution
Detailed explanation
\({A^2} + 4A - 51 = A \times A + 4A - 5I\)…
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