JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Let \(A_1, A_2, A_3\) be the three A.P. with the same common difference \(d\) and having their first terms as \(A , A +1, A +2\), respectively. Let \(a , b , c\) be the \(7^{\text {th }}, 9^{\text {th }}, 17^{\text {th }}\) terms of \(A_1, A_2, A_3\), respectively such that \(\left|\begin{array}{lll} a & 7 & 1 \\ 2 b & 17 & 1 \\ c & 17 & 1\end{array}\right|+70=0\) If \(a=29\), then the sum of first \(20\) terms of an \(AP\) whose first term is \(c - a - b\) and common difference is \(\frac{ d }{12}\), is equal to \(........\).
- A \(494\)
- B \(495\)
- C \(496\)
- D \(498\)
Answer & Solution
Correct Answer
(B) \(495\)
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{lll}A+6 d & 7 & 1 \\ 2(A+1+8 d) & 17 & 1 \\ A+2+16 d & 17 & 1\end{array}\right|+70=0\) \(\Rightarrow A=-7 \text { and } d =6\) \(\therefore c - a - b =20\) \(S _{20}=495\)
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