JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
If the total energy transferred to a surface in time \(t\) is \(6.48 \times 10^5 \mathrm{~J}\), then the magnitude of the total momentum delivered to this surface for complete absorption will be _______.
- A \(2.46 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)
- B \(2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)
- C \(1.58 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)
- D \(4.32 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(B) \(2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{p}=\frac{\mathrm{E}}{\mathrm{C}}=\frac{6.48 \times 10^5}{3 \times 10^8}=2.16 \times 10^{-3}\)
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