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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2024
  • Hard
  • MCQ

If the total energy transferred to a surface in time \(t\) is \(6.48 \times 10^5 \mathrm{~J}\), then the magnitude of the total momentum delivered to this surface for complete absorption will be _______.

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Answer & Solution

Correct Answer

(B) \(2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{p}=\frac{\mathrm{E}}{\mathrm{C}}=\frac{6.48 \times 10^5}{3 \times 10^8}=2.16 \times 10^{-3}\)
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