JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2024
- Medium
- MCQ
\(C_1\) and \(C_2\) are two hollow concentric cubes enclosing charges \(2 Q\) and \(3 Q\) respectively as shown in figure. The ratio of electric flux passing through \(C_1\) and \(C_2\) is _______.

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2: 5\)
Step-by-step Solution
Detailed explanation
Flux through \(C_1, \phi_1=\frac{q_{\text {in }}}{\varepsilon_0}=\frac{2 Q}{\varepsilon_0}\)
Flux through \(C_2, \phi_2=\frac{q_{\text {in }}}{\varepsilon_0}=\frac{2 Q+3 Q}{\varepsilon_0}=\frac{5 Q}{\varepsilon_0}\)
\(\frac{C_1}{C_2}=\frac{\phi_1}{\phi_2}=\frac{2 Q / \varepsilon_0}{5 Q / \varepsilon_0}=\frac{2}{5}\)
Flux through \(C_2, \phi_2=\frac{q_{\text {in }}}{\varepsilon_0}=\frac{2 Q+3 Q}{\varepsilon_0}=\frac{5 Q}{\varepsilon_0}\)
\(\frac{C_1}{C_2}=\frac{\phi_1}{\phi_2}=\frac{2 Q / \varepsilon_0}{5 Q / \varepsilon_0}=\frac{2}{5}\)
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