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JEE Mains · Maths · STD 11 - 14. probability
Two dices are rolled. If both dices have six faces numbered \(1,2,3,5,7\) and \(11,\) then the probability that the sum of the numbers on the top faces is less than or equal to \(8\) is
- A \(\frac{4}{9}\)
- B \(\frac{17}{36}\)
- C \(\frac{5}{12}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{17}{36}\)
Step-by-step Solution
Detailed explanation
\(n ( E )=5+4+4+3+1=17\) So, \(P(E)=\frac{17}{36}\)
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