JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2022
- Medium
- Numerical
Three identical spheres each of mass \(M\) are placed at the corners of a right angled triangle with mutually perpendicular sides equal to \(3\,m\) each. Taking point of intersection of mutually perpendicular sides as origin, the magnitude of position vector of centre of mass of the system will be \(\sqrt{x} m\). The value of \(x\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ r }_{\text {com }}=\frac{ M (0 \hat{ i }+0 \hat{ j })+ M (3 \hat{ i })+ M (3 \hat{ j })}{3 M }\)
\(\overrightarrow{ r }_{\text {coma }}=\hat{ i }+\hat{ j }\)
\(\left|\overrightarrow{ r }_{\text {com }}\right|=\sqrt{2}=\sqrt{ x }\)
\(x =2\)
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