JEE Mains · Physics · STD 11 - 11. thermodynamics
A Carnot engine operating between two reservoirs has efficiency \(\frac{1}{3}\). When the temperature of cold reservoir raised by \(x\), its efficiency decreases to \(\frac{1}{6}\). The value of \(x\), if the temperature of hot reservoir is \(99^{\circ}\,C\), will be \(........\,K\)
- A \(16.5\)
- B \(33\)
- C \(66\)
- D \(62\)
Answer & Solution
Correct Answer
(D) \(62\)
Step-by-step Solution
Detailed explanation
\(T _{ H }=99^{\circ} C =99+273\) \(\qquad=372\,K\) \(1-\frac{ T _{ C }}{ T _{ H }}=\frac{1}{3}\) \(\frac{ T _{ C }}{ T _{ H }}=\frac{2}{3} \quad(1) \Rightarrow T _{ C }=\frac{2}{3} \times 372\) \(1-\frac{ T _{ C }+ X }{ T _{ H }}=\frac{1}{6}\)…
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