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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2025
  • Easy
  • MCQ

The electric flux is \(\phi=\alpha \sigma+\beta \lambda\) where \(\lambda\) and \(\sigma\) are linear and surface charge density, respectively. \(\left(\frac{\alpha}{\beta}\right)\) represents

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(D) displacement

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\(\begin{aligned} & \alpha \equiv \frac{\phi}{\sigma} \\ & \beta=\frac{\phi}{\lambda} \\ & \frac{\alpha}{\beta} \equiv \frac{\lambda}{\sigma} \equiv \text { displacement }\end{aligned}\)
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