JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The electric flux is \(\phi=\alpha \sigma+\beta \lambda\) where \(\lambda\) and \(\sigma\) are linear and surface charge density, respectively. \(\left(\frac{\alpha}{\beta}\right)\) represents
- A electric field
- B area
- C charge
- D displacement
Answer & Solution
Correct Answer
(D) displacement
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \alpha \equiv \frac{\phi}{\sigma} \\ & \beta=\frac{\phi}{\lambda} \\ & \frac{\alpha}{\beta} \equiv \frac{\lambda}{\sigma} \equiv \text { displacement }\end{aligned}\)
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