JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2020
- Medium
- MCQ
Match the \(\frac{C _{ P }}{ C _{ v }}\) ratio for ideal gases with different type of molecules
| Moleculae type | \(\frac{C _{ P }}{ C _{ v }}\) |
| \((A)\) Monoatomic | \((I)\) \(\frac{7}{ 5}\) |
| \((B)\) Diatomic rigid molecules | \((II)\) \(\frac{9}{7}\) |
| \((C)\) Diatomic non-rigid molecules | \((III)\) \(\frac{4}{3}\) |
| \((D)\) Triatomic rigid molecules | \((IV)\) \(\frac{5}{3}\) |
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(A-IV, B-I, C-II, D-III\)
Step-by-step Solution
Detailed explanation
\(\gamma=\frac{ C _{ p }}{ C _{ v }}=1+\frac{2}{ f }\)
where \('f'\) is degree of freedom
\((A)\) Monoatomic \(f=3, \gamma=1+\frac{2}{3}=\frac{5}{3}\)
\((B)\) Diatomic rigid molecules,
\(f=5, \gamma=1+\frac{2}{3}=\frac{7}{5}\)
\((C)\) Diatomic non-rigid molecules
\(f=7, \gamma=1+\frac{2}{7}=\frac{9}{7}\)
\((D)\) Triatomic rigid molecules
\(f=6, \gamma=1+\frac{2}{6}=\frac{4}{3}\)
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