JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A solenoid has a core made of material with relative permeability \(400\). The magnetic field produced in the interior of solenoid is \(1.0\) T. The magnetic intensity in SI units is \(\alpha \times 10^5\). The value of \(\alpha\) is ______.
(Free space permeability \(\mu_0=4\pi \times 10^{-7}\) SI units.)
- A \(\dfrac{25}{\pi}\)
- B \(\dfrac{1}{16\pi}\)
- C \(\dfrac{1}{\pi}\)
- D \(\dfrac{1}{4\pi}\)
Answer & Solution
Correct Answer
(B) \(\dfrac{1}{16\pi}\)
Step-by-step Solution
Detailed explanation
The magnetic field \(B\) inside the solenoid is related to the magnetic intensity \(H\) by the formula: \(B = \mu H = \mu_0 \mu_r H\) Rearranging for \(H\), we get: \(H = \dfrac{B}{\mu_0 \mu_r}\) Substituting the given values (\(B = 1.0\) T, \(\mu_r = 400\), and…
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