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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2022
  • Medium
  • Numerical

In the circuit shown below, maximum zener diode current will be \(.....mA\)

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Answer & Solution

Correct Answer

(A) \(9\)

Step-by-step Solution

Detailed explanation

\(I =\frac{(120-60)\,V }{4000\,\Omega}=0.015\,A\)

Thus \(\quad I _{2}= I - I _{ L }\)

\(=0.015-0.006=0.009 A =9\,mA\)

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