JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In the circuit shown below, maximum zener diode current will be \(.....mA\)
- A \(9\)
- B \(90\)
- C \(95\)
- D \(45\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
\(I =\frac{(120-60)\,V }{4000\,\Omega}=0.015\,A\) Thus \(\quad I _{2}= I - I _{ L }\) \(=0.015-0.006=0.009 A =9\,mA\)
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