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JEE Mains · Physics · STD 11 - 13. oscillations
The displacement equations of two interfering waves are given by \(y_1 =10 \sin \left(\omega t+\frac{\pi}{3}\right) cm\) \(y_2 =5[\sin (\omega t)+\sqrt{3} \cos \omega t] \;cm\) respectively. The amplitude of the resultant wave is \(.............cm\).
- A \(18\)
- B \(17\)
- C \(20\)
- D \(16\)
Answer & Solution
Correct Answer
(C) \(20\)
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