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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2019
  • Medium
  • MCQ

The pressure wave, \(P = 0.01\,sin\,[1000t -3x]\,Nm^{-2},\) corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is \(0\,^oC.\) On some other day when temperature is \(T,\) the speed of sound produced by the same blade and at the same frequency is found to be \(336 \,ms^{-1}\). Approximate value of \(T\) is .... \(^oC\)

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Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

Speed of wave from wave equation

\(v=-\frac{(\text { coeffecient of } t)}{(\text { coeffecient of } x)}\)

\(v=-\frac{1000}{(-3)}=\frac{1000}{3}\)

since speed of wave \(\propto \sqrt{T}\)

\(\mathrm{So}=\frac{1000}{\frac{3}{336}}=\sqrt{\frac{273}{\mathrm{T}}}\)

\(\Rightarrow T=277.41 \mathrm{K}\)

\(\mathrm{T}=4.41^{\circ} \mathrm{C}\)

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