JEE Mains · Physics · STD 12 - 13. Nuclei
In a nuclear fission process, a high mass nuclide \((A \approx 236)\) with binding energy \(7.6\ \mathrm{MeV} /\) Nucleon dissociated into middle mass nuclides \((A \approx 118)\), having binding energy of \(8.6 \ \mathrm{MeV} / \mathrm{Nucleon}\). The energy released in the process would be \(\mathrm{MeV}\).
- A \(236\)
- B \(623\)
- C \(359\)
- D \(417\)
Answer & Solution
Correct Answer
(A) \(236\)
Step-by-step Solution
Detailed explanation
\( \mathrm{Q}=\mathrm{BE}_{\text {Product }}-\mathrm{BE}_{\text {Rectant }} \) \( =2(118)(8.6)-236(7.6) \) \( =236 \times 1=236 \mathrm{MeV}\)
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