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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2022
  • Medium
  • Numerical

\(7\) mole of certain monoatomic ideal gas undergoes a temperature increase of \(40 K\) at constant pressure. The increase in the internal energy of the gas in this process is\(....J\) (Given \(R =8.3 JK ^{-1} mol ^{-1}\) )

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Correct Answer

(B) \(3486\)

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Detailed explanation

For a quasi-static process the change in internal energy of an ideal gas is
\(\Delta U = nC _{ V } \Delta T\)
\(= n \times \frac{3 R }{2} \times \Delta T\)
[molar heat capacity at constant volume for mono atomic gas \(=\frac{3 R}{2}\) ]
\(\Delta U =7 \times \frac{3}{2} \times 8.3 \times 40=3486\,J\)
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