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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2019
  • Hard
  • MCQ

Surface of certain metal is first illuminated with light of wavelength \({\lambda _1} = 350\,nm\) and then, the light of wavelength \({\lambda _2} = 540\,nm\). It is found that the maximum speed of the photo electrons in the two cases differ by a factor of \(2\). The work function of the metal (in \(eV\)) is close to: (Energy of photon \( = \frac{{1240}}{{\lambda {\rm{(in\, nm)}}}}\,eV\))

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Answer & Solution

Correct Answer

(A) \(1.8\)

Step-by-step Solution

Detailed explanation

\(\frac{1240}{350}-\phi=(\mathrm{KE})_{1}=4 \mathrm{x}\)  ..... \((1)\)

\(\frac{1240}{540}-\phi=(\mathrm{KE})_{11}=x\) ...... \((2)\)

 \((1)\,\,-\,\,(2)\)

\(\frac{1240}{350}-\frac{1240}{540}=3.542-2.296=3 x\)

\(1.246=3 x ; \quad x=0.41\)

\(\phi=2.296-0.41=1.886\)

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