JEE Mains · Physics · STD 11 - Friction
- JEE Mains 2023
- Medium
- Numerical
A coin placed on a rotating table just slips when it is placed at a distance of \(1\,cm\) from the center. If the angular velocity of the table in halved, it will just slip when placed at a distance of from the centre \(............\,cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
\(f _{ s \max }=\mu mg = m \omega^2 R \Rightarrow R =\frac{\mu g }{\omega^2}\)
So if \(\omega\) becomes \(\frac{\omega}{2}, R\) will become \(4 R\).
So distance from the center will be \(4\,cm\).
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