JEE Mains · Maths · STD 12 - 7.2 definite integral
\(\int_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x\) is equal to
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{6}\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(D) \(2 \pi\)
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