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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry

A bakelite beaker has volume capacity of \(500\, cc\) at \(30^{\circ} C\). When it is partially filled with \(V _{ m }\) volume (at \(30^{\circ}\) ) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If \(\gamma_{\text {(beaker) }}=6 \times 10^{-6}{ }^{\circ} C ^{-1}\) and \(\gamma_{(\text {mercury })}=1.5 \times 10^{-4}{ }^{\circ} C ^{-1},\) where \(\gamma\) is the coefficient of volume expansion, then \(V _{ m }(\)in \(cc )\) is close to

  1. A \(20\)
  2. B \(25\)
  3. C \(35\)
  4. D \(27\)
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Answer & Solution

Correct Answer

(A) \(20\)

Step-by-step Solution

Detailed explanation

\(\Delta V =\left( V _{0}- V _{ m }\right)\) After increasing temperature \(\Delta V ^{\prime}=\left( V _{0}^{\prime}- V _{ m }^{\prime}\right)\) \(\Delta V ^{\prime}=\Delta V\)…
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