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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The change in the magnitude of the volume of an ideal gas when a small additional pressure \(\Delta P\) is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity \(\Delta T\) at constant pressure. The initial temperature and pressure of the gas were \(300\, K\) and \(2\; atm\) respectively. If \(|\Delta T|=C|\Delta P|\) then value of \(C\) in \((K / a t m)\) is......
- A \(150\)
- B \(176\)
- C \(145\)
- D \(135\)
Answer & Solution
Correct Answer
(A) \(150\)
Step-by-step Solution
Detailed explanation
\(PV = nRT\) \(P \Delta V + V \Delta P =0 \quad(\) for constant temp. \()\) \(P \Delta V = n R \Delta T \quad(\) for constant pressure) \(\Delta T =\frac{ P \Delta V }{ nR }\) \(\Delta P =-\frac{ P \Delta V }{ V } \quad(\Delta V\) is same in both cases \()\)…
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