JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

N equally spaced charges each of value q , are placed on a circle of radius R . The circle rotates about its axis with an angular velocity \(\omega\) as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, \(I_A-I_B\), for the given Amperian loops is:
- A \(\frac{2 \pi}{N} q \omega\)
- B \(\frac{\mathrm{N}^2}{2 \pi} \mathrm{q} \omega\)
- C \(\frac{\mathrm{N}}{\pi} \mathrm{q} \omega\)
- D \(\frac{\mathrm{N}}{2 \pi} \mathrm{q} \omega\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{N}}{2 \pi} \mathrm{q} \omega\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & I_A=\frac{N q}{\frac{2 \pi}{\omega}} \\ & I_A=\frac{N q \omega}{2 \pi}, I_B=0 \\ & I_A=I_B=\frac{N q \omega}{2 \pi}\end{aligned}\)
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