JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2014
- Hard
- MCQ
In the experiment of calibration of voltmeter, a standard cell of \(e.m.f\,\,1.1\,volt\) is balanced against \(440\,cm\) of potential wire. The potential difference across the ends of resistance is found to balance against \(220\,cm\) of the wire. The corresponding reading of voltmeter is \(0.5\,volt.\) The error in the reading of volmeter will be .................. \(volt\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(-0.05\)
Step-by-step Solution
Detailed explanation
In a voltmeter
\(V \propto l\)
\(\mathrm{V}=\mathrm{k} l\)
Now, it is given \(\mathrm{E}=1.1\) \(volt\) for \(l_{1}=440\, \mathrm{cm}\) and \(V=0.5\) \(volt\) for \(l_{2}=220\, \mathrm{cm}\)
Let the error in reading of voltmeter be \(\Delta \mathrm{V}\) then, \(1.1=400\, \mathrm{K}\) and \((0.5-\Delta \mathrm{V})=220\, \mathrm{K}\)
\(\Rightarrow \frac{1.1}{440}=\frac{0.5-\Delta V}{220}\)
\(\therefore \) \(\Delta V=-0.05 \text { volt }\)
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