JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A light rope is wound around a hollow cylinder of mass \(5\,kg\) and radius \(70\,cm\). The rope is pulled with a force of \(52.5\,N\). The angular acceleration of the cylinder will be.....\( {rad \,s}{ }^{-2}\).
- A \(14\)
- B \(15\)
- C \(13\)
- D \(12\)
Answer & Solution
Correct Answer
(B) \(15\)
Step-by-step Solution
Detailed explanation
\(\tau= I \alpha\) \(\Rightarrow FR = mR ^2 \alpha\) \(\alpha=\frac{ F }{ mR }=\frac{52.5}{5 \times 0.7}=15\,rad\,s ^{-2}\)
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