In the figure shown, a circuit contains two identical resistors with resistance \(R = 5\,\Omega \) and an inductance with \(L = 2\, mH\). An ideal battery of \(15\, V\) is connected in the circuit. What will be the current through the battery long after the switch is closed?......\(A\)

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(D) \(6\)

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After long time, inductor will behave like resistance less wire,

\(\mathrm{i}=\frac{15}{\mathrm{R}_{\mathrm{m}}}=\frac{15}{(5 / 2)}\)

\(=6 \,\mathrm{A}\)

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