JEE Mains · Physics · STD 12 -7. Alternating current
For an \(RLC\) circuit driven with voltage of amplitude \(v_m\) and frequency \({\omega _0} = \frac{1}{{\sqrt {LC} }}\) the current exhibits resonance. The quality factor, \(Q\) is given by:
- A \(\frac{{{\omega _0}R}}{L}\)
- B \(\frac{R}{{\left( {{\omega _0}C} \right)}}\)
- C \(\;\frac{{CR}}{{{\omega _0}}}\)
- D \(\frac{{{\omega _0}L}}{R}\)
Answer & Solution
Correct Answer
(D) \(\frac{{{\omega _0}L}}{R}\)
Step-by-step Solution
Detailed explanation
Quality factor \(Q=\frac{\omega_{0}}{2 \Delta \omega}=\frac{\omega_{0} L}{R}\)
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