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JEE Mains · Physics · STD 11 - Surface tension
  • JEE Mains 2023
  • Hard
  • Numerical

There is an air bubble of radius \(1.0\,mm\) in a liquid of surface tension \(0.075\,Nm ^{-1}\) and density \(1000\,kg\) \(m ^{-3}\) at a depth of \(10\,cm\) below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is \(....Pa \left( g =10\,ms ^{-2}\right)\)

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Answer & Solution

Correct Answer

(A) \(1150\)

Step-by-step Solution

Detailed explanation

Pressure inside the bubble

\(P=P_0+h \rho g+\frac{2 T}{r}\)

\(P-P_0=h \rho g+\frac{2 T}{r}\)

\(=0.1 \times 1000 \times 10+\frac{2 \times .075}{10^{-3}}\)

\(=1000+(0.15)(1000)\)

\(=1150\,Pa\)

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