JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2014
- Hard
- MCQ
The circuit shown here has two batteries of \(8.0\,V\) and \(16.0\,V\) and three resistors \(3\,\Omega ,\,9\,\Omega \) and \(9\,\Omega \) and a capacitor of \(5.0\,\mu F.\) How much is the current \(I\) in the circuit in steady state? ................... \(A\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(0.67\)
Step-by-step Solution
Detailed explanation
In steady state capacitor is fully charged hence no current will flow through line \(2\) .
Bysimplyfing the circuit
Hence resultant potential difference across resistances will be \(8.0 \,\mathrm{V}\)
Thus current \(1=\frac{V}{R}=\frac{8.0}{3+9}=\frac{8}{12}\)
or, \(\quad I=\frac{2}{3}=0.67\, \mathrm{A}\)
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