JEE Mains · Physics · STD 12 - 3. current electricity
A current of \(2\, mA\) was passed through an unknown resistor which dissipated a power of \(4.4\, W\). Dissipated power when an ideal power supply of \(11\, V\) is connected across it is
- A \(11\times10^{-5}\, W\)
- B \(11\times10^{-3}\, W\)
- C \(11\times10^{-4}\, W\)
- D \(11\times10^{5}\, W\)
Answer & Solution
Correct Answer
(A) \(11\times10^{-5}\, W\)
Step-by-step Solution
Detailed explanation
\(R =\frac{P}{l^{2}}=\frac{4.4}{4 \times 10^{-6}} \,\Omega \) \( P^{\prime}= \frac{V^{2}}{R}=\frac{11 \times 11 \times 4 \times 10^{-6}}{4.4} \,W \) \(=11 \times 10^{-5} \,W \)
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