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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • MCQ

A current of \(2\, mA\) was passed through an unknown resistor which dissipated a power of \(4.4\, W\). Dissipated power when an ideal power supply of \(11\, V\) is connected across it is

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Answer & Solution

Correct Answer

(A) \(11\times10^{-5}\, W\)

Step-by-step Solution

Detailed explanation

\(R =\frac{P}{l^{2}}=\frac{4.4}{4 \times 10^{-6}} \,\Omega \)

\( P^{\prime}= \frac{V^{2}}{R}=\frac{11 \times 11 \times 4 \times 10^{-6}}{4.4} \,W \)

\(=11 \times 10^{-5} \,W \)

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