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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2022
  • Easy
  • MCQ

A block of mass \(M\) placed inside a box descends vertically with acceleration \('a'\). The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of \('a'\) will be .............

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Answer & Solution

Correct Answer

(C) \(\frac{3 g }{4}\)

Step-by-step Solution

Detailed explanation

\(m g-N=m a\)

\(a=g-\frac{g}{4}\)

\(a=\frac{3 g}{4}\)

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