In an \(LCR \) circuit as shown below both switches are open initially. Now switch \(S_1\) is closed, \(S_2\) kept open. ( \(q\) is charge on the capacitor and \(\tau = RC\) is Capacitive time constant). Which of the following statement is correct?

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Answer & Solution

Correct Answer

(D) At \(t= \)\({2 \tau }\) ,\(q=CV\) \((1-e^{-2})\)

Step-by-step Solution

Detailed explanation

Charge on he capacitor at any time \(t\) is given by

\(q=C V\left(1-e^{t / \tau}\right)\)

at \(t=2 \tau\)

\(q=C V\left(1-e^{-2}\right)\)

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