JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
In an experiment on photoelectric effect, a student plots stopping potential \(V_0\) against reciprocal of the wavelength \(\lambda \) of the incident light for two different metals \(A\) and \(B\). These are shown in the figure Looking at the graphs, you can most appropriately say that
- A Work function of metal \(B\) is greater than that of metal \(A\)
- B For light of certain wavelength falling on both metal, maximum kinetic energy of electrons emitted from \(A\) will be greater than those emitted from \(B\)
- C Work function of metal \(A\) is greater than that of metal \(B\)
- D Students data is not correct
Answer & Solution
Correct Answer
(D) Students data is not correct
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{hc}}{\lambda}-\phi=\mathrm{eV}_{0}\) \(v_{0}=\frac{h c}{e \lambda}-\frac{\phi}{e}\) For metal \(A\) For metal \(B\) \(\frac{{\phi A}}{{hc}} = \frac{1}{\lambda }\) \(\frac{{\phi B}}{{hc}} = \frac{1}{\lambda }\) As the value of \(\frac{1}{\lambda}\) (increasing and…
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