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JEE Mains · Physics · STD 11 - 2. motion in straight line

A body moves on a frictionless plane starting from rest. If \(\mathrm{S}_{\mathrm{n}}\) is distance moved between \(\mathrm{t}=\mathrm{n}-1\) and \(\mathrm{t}\) \(=\mathrm{n}\) and \(\mathrm{S}_{\mathrm{n}-1}\) is distance moved between \(\mathrm{t}=\mathrm{n}-2\) and \(t=n-1\), then the ratio \(\frac{S_{n-1}}{S_n}\) is \(\left(1-\frac{2}{x}\right)\) for \(n\) \(=10\). The value of \(x\) is _______.

  1. A \(18\)
  2. B \(19\)
  3. C \(20\)
  4. D \(21\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(19\)

Step-by-step Solution

Detailed explanation

\(\mathrm{S}_{\mathrm{n}}=\frac{1}{2} \mathrm{a}(2 \mathrm{n}-1)=\frac{19 \mathrm{a}}{2}\) \(\mathrm{~S}_{\mathrm{n}-1}=\frac{1}{2} \mathrm{a}(2 \mathrm{n}-3)=\frac{17 \mathrm{a}}{2}\)…
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