JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2021
- Hard
- Numerical
A sample of gas with \(\gamma=1.5\) is taken through an adiabatic process in which the volume is compressed from \(1200\, {cm}^{3}\) to \(300\, {cm}^{3}\). If the initial pressure is \(200\, {kPa}\). The absolute value of the workdone by the gas in the process \(= \,..... J.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(480\)
Step-by-step Solution
Detailed explanation
\(\gamma=1.5\)
\(p_{1} v_{1}^{\gamma}=p_{2} v_{2}^{\gamma}\)
\((200)(1200)^{1.5}=P^{2}(300)^{1.5}\)
\(P_{2}=200[4]^{3 / 2}=1600 {kPa}\)
\(\mid\) W.D. \(\mid=\frac{{p}_{2} {v}_{2}-{p}_{1} {v}_{1}}{v-1}=\left(\frac{480-240}{0.5}\right)=480 {J}\)
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