JEE Mains · Physics · STD 11 - 11. thermodynamics
A sample of gas with \(\gamma=1.5\) is taken through an adiabatic process in which the volume is compressed from \(1200\, {cm}^{3}\) to \(300\, {cm}^{3}\). If the initial pressure is \(200\, {kPa}\). The absolute value of the workdone by the gas in the process \(= \,..... J.\)
- A \(0.5\)
- B \(240\)
- C \(48\)
- D \(480\)
Answer & Solution
Correct Answer
(D) \(480\)
Step-by-step Solution
Detailed explanation
\(\gamma=1.5\) \(p_{1} v_{1}^{\gamma}=p_{2} v_{2}^{\gamma}\) \((200)(1200)^{1.5}=P^{2}(300)^{1.5}\) \(P_{2}=200[4]^{3 / 2}=1600 {kPa}\) \(\mid\) W.D. \(\mid=\frac{{p}_{2} {v}_{2}-{p}_{1} {v}_{1}}{v-1}=\left(\frac{480-240}{0.5}\right)=480 {J}\)
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