JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If the eccentricity of the standard hyperbola passing, through the point \((4, 6)\) is \(2\), then the equation of the tangent to the hyperbola at \((4, 6)\) is
- A \(2x -3y + 10 = 0\)
- B \(x -2y + 8 = 0\)
- C \(2x -y -2 = 0\)
- D \(3x -2y = 0\)
Answer & Solution
Correct Answer
(C) \(2x -y -2 = 0\)
Step-by-step Solution
Detailed explanation
Let equation of hyperbola be \(\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1\,\,\) passes through \(\left( {4,6} \right)\) \( \Rightarrow \frac{{16}}{{{a^2}}} - \frac{{36}}{{{b^2}}} = 1\,\,\,\,\,\,\,.....\left( i \right)\) Also…
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