JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2021
- Hard
- Numerical
If one wants to remove all the mass of the earth to infinity in order to break it up completely. The amount of energy that needs to be supplied will be \(\frac{x}{5}\, \frac{ GM ^{2}}{ R }\) where \(x\) is \(\quad\,..........\) (Round off to the Nearest Integer) (\(M\) is the mass of earth, \(R\) is the radius of earth, \(G\) is the gravitational constant)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
Energy given \(= U _{ f }- U _{ i }\)
\(=0-\left(-\frac{3}{5} \frac{ GM ^{2}}{ R }\right)\)
\(=\frac{3}{5} \frac{ GM ^{2}}{ R }\)
\(x =3\)
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