If \(\overrightarrow{\mathrm{L}}\) and \(\overrightarrow{\mathrm{P}}\) represent the angular momentum and linear momentum respectively of a particle of mass ' m ' having position vector \(\overrightarrow{\mathrm{r}}=\mathrm{a}(\hat{\mathrm{i}} \cos \omega \mathrm{t}+\hat{\mathrm{j}} \sin \omega \mathrm{t})\). The direction of force is

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Correct Answer

(A) Opposite to the direction of \(\vec{r}\)

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Detailed explanation

\(\overrightarrow{\mathrm{a}}=-\omega^2 \overrightarrow{\mathrm{r}}\)
\(\therefore \overrightarrow{\mathrm{F}}\) opposite to \(\overrightarrow{\mathrm{r}}-\)

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