JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A bag of sand of mass \(9.8\,kg\) is suspended by a rope. A bullet of \(200 \,g\) travelling with speed \(10\, ms ^{-1}\) gets embedded in it, then loss of kinetic energy will be \(...J\)
- A \(4.9\)
- B \(9.8\)
- C \(14.7\)
- D \(19.6\)
Answer & Solution
Correct Answer
(B) \(9.8\)
Step-by-step Solution
Detailed explanation
\(P _{ i }= P _{ f }\) (no any external force) \(0.2 \times 10=10 \times v\) \(v =0.2 m / sec\) Loss in K.E. \(=\frac{1}{2} \times(0.2) \times 10^{2}-\frac{1}{2} \times 10(0.2)^{2}\) \(=\frac{1}{2} \times 10 \times(0.2)[10-0.2]\) \(=9.8\,J\)
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