JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
Heat energy of \(184\,kJ\) is given to ice of mass \(600\,g\) at \(-12^{\circ}\,C\), Specific heat of ice is \(2222.3\,J\,kg ^{-1^{\circ}}\,C ^{-1}\) and latent heat of ice in \(336\,kJ / kg ^{-1}\) \((A)\) Final temperature of system will be \(0^{\circ} C\). \((B)\) Final temperature of the system will be greater than \(0^{\circ} C\). \((C)\) The final system will have a mixture of ice and water in the ratio of \(5: 1\). \((D)\) The final system will have a mixture of ice and water in the ratio of \(1: 5\). \((E)\) The final system will have water only. Choose the correct answer from the options given below:
- A \(A\) and \(D\) only
- B \(B\) and \(D\) only
- C \(A\) and \(E\) only
- D \(A\) and \(C\) only
Answer & Solution
Correct Answer
(A) \(A\) and \(D\) only
Step-by-step Solution
Detailed explanation
\(\Delta Q =184 \times 10^3\) \(m =0.600\,kg \text { at }-12^{\circ}\,C\) \(S =222.3\,J / kg /{ }^{\circ}\,C\) \(L =336 \times 10^3 \,J / kg\) \(Q _1=0.600 \times 2222.3 \times 12=16000.56\,J\) Remaining heat \(\Delta Q _1=184000-16000.56\) \(=167999.44\,J\) For meeting at…
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