JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2023
- Hard
- MCQ
Heat energy of \(184\,kJ\) is given to ice of mass \(600\,g\) at \(-12^{\circ}\,C\), Specific heat of ice is \(2222.3\,J\,kg ^{-1^{\circ}}\,C ^{-1}\) and latent heat of ice in \(336\,kJ / kg ^{-1}\) \((A)\) Final temperature of system will be \(0^{\circ} C\). \((B)\) Final temperature of the system will be greater than \(0^{\circ} C\). \((C)\) The final system will have a mixture of ice and water in the ratio of \(5: 1\). \((D)\) The final system will have a mixture of ice and water in the ratio of \(1: 5\). \((E)\) The final system will have water only. Choose the correct answer from the options given below:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(A\) and \(D\) only
Step-by-step Solution
Detailed explanation
\(\Delta Q =184 \times 10^3\)
\(m =0.600\,kg \text { at }-12^{\circ}\,C\)
\(S =222.3\,J / kg /{ }^{\circ}\,C\)
\(L =336 \times 10^3 \,J / kg\)
\(Q _1=0.600 \times 2222.3 \times 12=16000.56\,J\)
Remaining heat \(\Delta Q _1=184000-16000.56\)
\(=167999.44\,J\)
For meeting at \(0^{\circ}\,C\)
\(\Delta Q _2=0.600 \times 336000=201600\,J \text { needed }\)
\(\therefore 100 \%\) ice is not melted
Amount of ice melted
\(167999.44= m \times 336000=0.4999\,kg\)
\(\therefore\) mass of water \(=0.4999\,kg\)
Mass of ice \(=0.1001\)
\(\therefore\) Ratio \(=\frac{0.1001}{0.4999} \approx 1: 5\)
More questions from Physics
- The distance between two consecutive points with phase difference of \(60^{\circ}\) in a wave of frequency \(500\,Hz\) is \(6.0\,m\). The velocity with which wave is traveling is \(.........km / s\)JEE Mains 2023 Hard
- In the circuit shown, a four wire potentiometer is made of a \(400\, cm\) long wire, which extends between \(A\) and \(B\). The resistance per unit length of the potentiometer wire is \(r = 0.01\, \Omega /cm\). If an ideal voltmeter is connected as shown with jockey \(J\) at \(50\, cm\) from end \(A\), the expected reading of the voltmeter will be: ............... \(V\)
JEE Mains 2019 Medium - A beaker contains a fluid of density \(\rho \, kg / m^3\), specific heat \(S\, J / kg\,^oC\) and viscosity \(\eta \). The beaker is filled upto height \(h\). To estimate the rate of heat transfer per unit area \((Q / A)\) by convection when beaker is put on a hot plate, a student proposes that it should depend on \(\eta \,,\,\left( {\frac{{S\Delta \theta }}{h}} \right)\) and \(\left( {\frac{1}{{\rho g}}} \right)\) when \(\Delta \theta \) (in \(^oC\)) is the difference in the temperature between the bottom and top of the fluid. In that situation the correct option for \((Q / A)\) isJEE Mains 2015 Hard
- The equivalent resistance between \(A\) and \(B\) is _______.
JEE Mains 2024 Hard - Statement \(I:\) If three forces \(\vec{F}_{1}, \vec{F}_{2}\) and \(\vec{F}_{3}\) are represented by three sides of a triangle and \(\overrightarrow{{F}}_{1}+\overrightarrow{{F}}_{2}=-\overrightarrow{{F}}_{3}\), then these three forces are concurrent forces and satisfy the condition for equilibrium. Statement \(II:\) A triangle made up of three forces \(\overrightarrow{{F}}_{1}, \overrightarrow{{F}}_{2}\) and \(\overrightarrow{{F}}_{3}\) as its sides taken in the same order, satisfy the condition for translatory equilibrium. In the light of the above statements, choose the most appropriate answer from the options given below:JEE Mains 2021 Medium
- A capacitor of capacitance \(100\ \mu \mathrm{F}\) is charged to a potential of \(12 \mathrm{~V}\) and connected to a \(6.4 \ \mathrm{mH}\) inductor to produce oscillations. The maximum current in the circuit would be :JEE Mains 2024 Hard
More PYQs from JEE Mains
- A common emitter amplifier circuit, built using an \(npn\) transistor, is shown in the figure. Its \(dc\) current gain is \(250\), \(R_C = 1\,k\, \Omega \) and \(V_{CC} = 10\,V\). What is the minimum base current for \(V_{CE}\) to reach saturation?.........\(\mu A\)
JEE Mains 2019 Medium - A slab of dielectric constant \(K\) has the same crosssectional area as the plates of a parallel plate capacitor and thickness \(\frac{3}{4}\,d\), where \(d\) is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be.(Given \(C _{0}=\) capacitance of capacitor with air as medium between plates.)JEE Mains 2022 Hard