- JEE Mains 2023
- Medium
- MCQ
Math List \(I\) with List \(II\) Choose the correct answer from the option given below:

Answer & Solution
(C) \(A-III, B-I, C-IV, D-II\)
Step-by-step Solution
Detailed explanation
\(B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }\)
\(B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(2 \pi) \text { (in the plane) }\)
\(B _{ de }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }\)
Hence magnetic field at \(O\) is
\(B _0=-\frac{\mu_0}{4 \pi} \frac{ I }{ r }+\frac{\mu_0}{4 \pi} \frac{ I }{ r }(2 \pi)-\frac{\mu_0}{4 \pi} \frac{ I }{ r }\)
\(B _0=\frac{\mu_0}{2 \pi} \frac{ I }{ r }(\pi-1) \ldots \ldots . . \text { (III) }\)
(B)
\(B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }\)
\(B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (out of the plane) }\)
\(B _{ de }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }\)
Hence magnetic field at \(O\) is
\(B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }+\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi)+\frac{\mu_0}{4 \pi} \frac{ I }{ r }\)
\(B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi+2) \ldots .( I )\)
(C)
\(B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (in the plane) }\)
\(B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (in the plane) }\)
\(B _{ de }=0 \text { (at the axis) }\)
Hence magnetic field at \(O\) is
\(B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(1+\pi) \ldots(IV)\)
\(B _{ ab }=0 \text { (at the axis) }\)
\(B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (out of the plane) }\)
\(B _{ de }=0 \text { (at the axis) }\)
Hence magnetic field at \(O\) is
\(B _0=\frac{\mu_0 I }{4 r } \ldots \text { (II) }\)
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