JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2026
- Hard
- MCQ
Given below are two statements:
Statement I: For a mechanical system of many particles total kinetic energy is the sum of kinetic energies of all the particles.
Statement II: The total kinetic energy can be the sum of kinetic energy of the center of mass w.r.t. to the origin and the kinetic energy of all the particles w.r.t. the center of mass as the reference.
In the light of the above statements,choose the correct answer from the options given below:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) Both Statement I and Statement II are true
Step-by-step Solution
Detailed explanation
\( KE=\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2} \)
\( KE=\frac{1}{2}(m_{1}+m_{2})v_{cm}^{2}+\frac{1}{2}\frac{m_{1}m_{2}}{m_{1}+m_{2}}|\vec{v}_{1}-\vec{v}_{2}|^{2} \)
So Ans. is (1)
\( KE=\frac{1}{2}(m_{1}+m_{2})v_{cm}^{2}+\frac{1}{2}\frac{m_{1}m_{2}}{m_{1}+m_{2}}|\vec{v}_{1}-\vec{v}_{2}|^{2} \)
So Ans. is (1)
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