JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let \(\mathrm{P}\) be a plane passing through the points \((1,0,1),(1,-2,1)\) and \((0,1,-2)\). Let a vector \(\vec{a}=\alpha \hat{i}+\beta \hat{j}+\gamma \hat{k}\) be such that \(\vec{a}\) is parallel to the plane \(P\), perpendicular to \((\hat{i}+2 \hat{j}+3 \hat{k})\) and \(\overrightarrow{\mathrm{a}} \cdot(\hat{\mathrm{i}}+\hat{\mathrm{j}}+2 \hat{\mathrm{k}})=2\), then \((\alpha-\beta+\gamma)^{2}\) equals \(....\)
- A \(81\)
- B \(84\)
- C \(89\)
- D \(18\)
Answer & Solution
Correct Answer
(A) \(81\)
Step-by-step Solution
Detailed explanation
\(\overline{\mathrm{a}}=\overline{\mathrm{n}}_{\mathrm{p}} \times(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}})\) \(\overline{\mathrm{a}}=(\overline{\mathrm{AB}} \times \overline{\mathrm{AC}}) \times(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}})\)…
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