JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2022
- Hard
- MCQ
Three identical charged balls each of charge \(2 \,C\) are suspended from a common point \(P\) by silk threads of \(2 \,m\) each (as shown in figure). They form an equilateral triangle of side \(1 \,m\). The ratio of net force on a charged ball to the force between any two charged balls will be ...........

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\sqrt{3}: 1\)
Step-by-step Solution
Detailed explanation
\(F=\frac{k(2)(2)}{(1)^{2}}\)
( \(F=\) Force between two charges).
\(F =4 k\)
\(F_{\text {net }}=2 F \cos 30^{\circ}=2 \cdot F \cdot \frac{\sqrt{3}}{2}=F \sqrt{3}\)
\(\left(F_{\text {net }}=\right.\) Net electrostatic force on one charged ball)
\(\frac{F_{\text {net }}}{F}=\frac{\sqrt{3} F}{F}=(\sqrt{3})\)
Remark : Net force on any one of the ball is zero. But no option given in options.
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