JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Three identical charged balls each of charge \(2 \,C\) are suspended from a common point \(P\) by silk threads of \(2 \,m\) each (as shown in figure). They form an equilateral triangle of side \(1 \,m\). The ratio of net force on a charged ball to the force between any two charged balls will be ...........
- A \(1: 1\)
- B \(1: 4\)
- C \(\sqrt{3}: 2\)
- D \(\sqrt{3}: 1\)
Answer & Solution
Correct Answer
(D) \(\sqrt{3}: 1\)
Step-by-step Solution
Detailed explanation
\(F=\frac{k(2)(2)}{(1)^{2}}\) ( \(F=\) Force between two charges). \(F =4 k\) \(F_{\text {net }}=2 F \cos 30^{\circ}=2 \cdot F \cdot \frac{\sqrt{3}}{2}=F \sqrt{3}\) \(\left(F_{\text {net }}=\right.\) Net electrostatic force on one charged ball)…
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