JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2020
- Medium
- MCQ
Three harmonic waves having equal frequency \(\mathrm{v}\) and same intensity \(\mathrm{I}_{0}\), have phase angles \(0 , \frac{\pi}{4}\) and \(-\frac{\pi}{4}\) respectively. When they are superimposed the intensity of the resultant wave is close to
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(5.8 \mathrm{I}_{0}\)
Step-by-step Solution
Detailed explanation
Let amplitude of each wave is \(A.\)
Resultant wave equation
\(=A \sin \omega t+A \sin \left(\omega t-\frac{\pi}{4}\right)+A \sin \left(\omega t+\frac{\pi}{4}\right)\)
\(=\mathrm{A} \sin \omega \mathrm{t}+\sqrt{2} \mathrm{A} \sin \omega \mathrm{t}\)
\(=(\sqrt{2}+1) \mathrm{A} \sin \omega \mathrm{t}\)
Resultant wave amplitude \(=(\sqrt{2}+1) \mathrm{A}\)
as \(I \propto A ^{2}\)
so \(\frac{\mathrm{I}}{\mathrm{I}_{0}}=(\sqrt{2}+1)^{2}\)
\(I=5.8 \mathrm{I}_{0}\)
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