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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2020
  • Medium
  • MCQ

Three harmonic waves having equal frequency \(\mathrm{v}\) and same intensity \(\mathrm{I}_{0}\), have phase angles \(0 , \frac{\pi}{4}\) and \(-\frac{\pi}{4}\) respectively. When they are superimposed the intensity of the resultant wave is close to

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Answer & Solution

Correct Answer

(A) \(5.8 \mathrm{I}_{0}\)

Step-by-step Solution

Detailed explanation

Let amplitude of each wave is \(A.\)

Resultant wave equation

\(=A \sin \omega t+A \sin \left(\omega t-\frac{\pi}{4}\right)+A \sin \left(\omega t+\frac{\pi}{4}\right)\)

\(=\mathrm{A} \sin \omega \mathrm{t}+\sqrt{2} \mathrm{A} \sin \omega \mathrm{t}\)

\(=(\sqrt{2}+1) \mathrm{A} \sin \omega \mathrm{t}\)

Resultant wave amplitude \(=(\sqrt{2}+1) \mathrm{A}\)

as \(I \propto A ^{2}\)

so \(\frac{\mathrm{I}}{\mathrm{I}_{0}}=(\sqrt{2}+1)^{2}\)

\(I=5.8 \mathrm{I}_{0}\)

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