JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
Consider an electromagnetic wave propagating in vacuum . Choose the correct statement
- A For an electromagnetic wave propagating in \(+y\) direction the electric field is \(\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\hat z\) and the magnetic field is \(\vec B = \frac{1}{{\sqrt 2 }}\,{B_z}\,\left( {x,t} \right)\hat y\)
- B For an electromagnetic wave propagating in \(+y\) direction the electric field is \(\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\hat y\) and the magnetic field is \(\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {x,t} \right)\hat z\)
- C For an electromagnetic wave propagating in \(+x\) direction the electric field is \(\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {y,z,t} \right)\,\left( {\hat y + \hat z} \right)\) and the magnetic field is \(\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {y,z,t} \right)\,\left( {\hat y + \hat z} \right)\)
- D For an electromagnetic wave propagating in \(+x\) direction the electric field is \(\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\left( {\hat y - \hat z} \right)\) and the magnetic field is \(\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {x,t} \right)\,\left( {\hat y + \hat z} \right)\)
Answer & Solution
Correct Answer
(D) For an electromagnetic wave propagating in \(+x\) direction the electric field is \(\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\left( {\hat y - \hat z} \right)\) and the magnetic field is \(\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {x,t} \right)\,\left( {\hat y + \hat z} \right)\)
Step-by-step Solution
Detailed explanation
Wave in \(X-\) direction means \(E\) and \(B\) should be function of \(x\) and \(t\) \(\overset\frown{y}-\overset\frown{z}\,\bot \,\overset\frown{y}+\overset\frown{z}\,\)
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