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JEE Mains · Maths · STD 11 - 7. binomial theoram
The ratio of the coefficient of \(x^{15}\) to the term independent of \(x\) in the expansion of \({\left( {{x^2} + \frac{2}{x}} \right)^{15}}\) is
- A \(7: 16\)
- B \(7:64\)
- C \(1: 4\)
- D \(1: 32\)
Answer & Solution
Correct Answer
(D) \(1: 32\)
Step-by-step Solution
Detailed explanation
\(T_{r+1}=^{15} C_{r}\left(x^{2}\right)^{15-r} \cdot\left(2 x^{-1}\right)^r\) \(=15 \mathrm{C}_{r} \times(2)^{r} \times x^{30-3r}\) For independent term, \(30-3 r=0\) \(\Rightarrow r=10\) Hence the term independent of \(x\).…
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