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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2023
  • Medium
  • MCQ

A planet having mass \(9\,Me\) and radius \(4 R _e\), where Me and \(\operatorname{Re}\) are mass and radius of earth respectively, has escape velocity in \(km / s\) given by:(Given escape velocity on earth \(\left.V_e=11.2 \times 10^3\,m / s \right)\)

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Answer & Solution

Correct Answer

(B) \(16.8\)

Step-by-step Solution

Detailed explanation

\(V_p=\sqrt{\frac{2 G_p}{R_p}} V_E=\sqrt{\frac{2 GM _E}{R_E}}\)

\(\frac{V_P}{V_E}=\frac{\sqrt{\frac{2 G_P}{R_p}}}{\sqrt{\frac{2 G_E}{R_E}}}=\sqrt{\frac{R_E}{R_P} \times \frac{M_P}{M_E}}\)

\(V_P=\sqrt{\frac{1}{4} \times 9} \times V_E=\frac{3}{2} V_E\)

\(V _{ P }=\frac{3}{2} \times 11.2\,km / sec\)

\(=16.8\,km / sec\)

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