JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2017
- Medium
- MCQ
\(c_P\) and \(c_V\) are specific heats at constant pressure and constant volume respectively. It is observed that \(c_P - c_V = a\) for hydrogen gas \(c_P - c_V = b\) for nitrogen gas The correct relation between \(a\) and \(b\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(a=14b\)
Step-by-step Solution
Detailed explanation
As we know, \(C_P-C_v=E\) where \(C_p\) and \(C_v\) are molar specific heat capacities
or, \({C_P} - {C_v} = \frac{R}{M}\)
For hydrogen \((M = 2){C_p} - {C_v} = a = \frac{R}{2}\)
\(For\,nitrogen\left( {M = 28} \right){C_p} - {C_v} = b = \frac{R}{{28}}\)
\(\therefore \,\frac{a}{b} = 14\,\,or,\,\,a = 14b\)
More questions from Physics
- Match List-I with List-II.
List-I List-II A. Meter (L) I. \(\sqrt{\dfrac{hc}{G}}\) B. Second (S) II. \(\sqrt{\dfrac{Gh}{c^5}}\) C. Kilogram (M) III. \(\sqrt{\dfrac{K^2L^2c^3}{Gh}}\) D. Kelvin (K) IV. \(\sqrt{\dfrac{Gh}{c^3}}\)
where \(h\) (Planck's constant), \(G\) (gravitational constant) and \(c\) (speed of light in vacuum) as fundamental units.
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