JEE Mains · Physics · STD 12 - 12. atoms
An \(X-\)ray tube is operated at \(1.24\) million volt. The shortest wavelength of the produced photon will be ..... \(nm\)
- A \(10^{-3}\)
- B \(10^{-1}\)
- C \(10^{-2}\)
- D \(10^{-4}\)
Answer & Solution
Correct Answer
(A) \(10^{-3}\)
Step-by-step Solution
Detailed explanation
\(\lambda_{\min }=\frac{1240}{\Delta V }( nm )\) \(=\frac{1240}{1.24 \times 10^{6}}=10^{-3} \,nm\)
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